(5x+2)(2x^2-17x-9)=0

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Solution for (5x+2)(2x^2-17x-9)=0 equation: 


Simplifying
(5x + 2)(2x2 + -17x + -9) = 0

Reorder the terms:
(2 + 5x)(2x2 + -17x + -9) = 0

Reorder the terms:
(2 + 5x)(-9 + -17x + 2x2) = 0

Multiply (2 + 5x) * (-9 + -17x + 2x2)
(2(-9 + -17x + 2x2) + 5x * (-9 + -17x + 2x2)) = 0
((-9 * 2 + -17x * 2 + 2x2 * 2) + 5x * (-9 + -17x + 2x2)) = 0
((-18 + -34x + 4x2) + 5x * (-9 + -17x + 2x2)) = 0
(-18 + -34x + 4x2 + (-9 * 5x + -17x * 5x + 2x2 * 5x)) = 0
(-18 + -34x + 4x2 + (-45x + -85x2 + 10x3)) = 0

Reorder the terms:
(-18 + -34x + -45x + 4x2 + -85x2 + 10x3) = 0

Combine like terms: -34x + -45x = -79x
(-18 + -79x + 4x2 + -85x2 + 10x3) = 0

Combine like terms: 4x2 + -85x2 = -81x2
(-18 + -79x + -81x2 + 10x3) = 0

Solving
-18 + -79x + -81x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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